Webb12 feb. 2024 · (a) Consider a class with 30 students. Compute the probability that at least two of them have their birthdays on the same day. (For simplicity, ignore the leap year.) … WebbCorrect option is D) One of the friends may have anyone day out of 365 days as birthday, similarly other friend may have one day out of 365 days as birthday. So total number of ways in which two friends have their birthday is 365 × 365. so P (both have the same b'day) =365/365×365=1/365.

Using the birthday paradox to teach probability fundamentals

Webb31 dec. 2024 · It was a class of about 30 students and the professor bet that at least two of us shared the same birthday. He then proceeded to have everyone state their … Webbwie to teach base math to kindergarteners hannover germany new town hall

Birthday probability problem (video) Khan Academy

WebbThis probability can be computed precisely based on analysis of the birthday problem. [22] For example, the number of random version-4 UUIDs which need to be generated in order to have a 50% probability of at least one collision is 2.71 quintillion, computed as follows: [23] WebbThe chance that the second person has the same birthday is 1/365. So, the probability that both have the same birthday is computed as: P (samebirthday) = 365 365 × 1 365 = 1 365 P ( s a m... Webb(This question is different from is there any student in your class who has the same birthday as you.) The answer in probability is quite surprising: in a group of at least 23 … ch 7 aspirus