If the eccentricity of the hyperbola is 5/4
Web9 jul. 2024 · Let the eccentricity of the hyperbola x2/a2 - y2/b2 = 1 be 5/4. If the equation of the normal at the point (8/√5, 12/5) on the hyperbola is 8√5x + ßy = λ, then λ - ß is equal to jee main 2024 1 Answer +1 vote answered Jul 9, 2024 by Swetakeshri (42.5k points) … Web11 sep. 2024 · Answer is (2) 4√5 3 4 5 3 Given θ ∈ (0,π/2) equation of hyperbola ⇒ x2–y2sec2θ = 10 Hence eccentricity of hyperbola Now equation of ellipse ⇒ x2sec2θ + y2 = 5 Hence eccenticity of ellipse Now length of latus rectum of ellipse ← Prev Question Next Question → JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ …
If the eccentricity of the hyperbola is 5/4
Did you know?
Web(a) the equation of the hyperbola is x2/3 – y2/2 = 1 (b) the eccentricity of the hyperbola is √ (5/3) (c) a focus of the hyperbola is (2, 0) (d) the equation of the hyperbola is x2 – 3y2 = 3 Answer: (d) Solution: The eccentricity of ellipse, e = √ (1-b2/a2) Given equation of ellipse x2 + 4y2 = 4 can be rewritten as x2/4 + y2/1 = 1. WebThe linear eccentricity (focal distance) is c = \sqrt {a^ {2} + b^ {2}} = 3 \sqrt {5} c = a2 + b2 = 3 5. The eccentricity is e = \frac {c} {a} = \frac {\sqrt {5}} {2} e = ac = 25. The first focus is \left (h - c, k\right) = \left (- 3 \sqrt {5}, 0\right) (h − c,k) = (−3 5,0).
WebThe eccentricity of a hyperbola is calculated using the length of the transverse axis and the length of the conjugate axis. Recall that hyperbolas are defined as the set of points in a plane, which have a difference of the distances from the two foci that is constant. Web1. The particular kind of hyperbola in which the lengths of the transverse and conjugate axis are equal is called an equilateral hyperbola. 2. Eccentricity of equilateral hyperbola = √ 2 3. Equation of pair of asymptotes of rectangular hyperbola x 2 − y 2 = a 2 is x 2 − y 2 = …
WebWe know the eccentricity of hyperbola is e = c/a c= √ (a 2 +b 2) c = 5 e 5/3 Thus the eccentricity of the given hyperbola is 5/3 Practice Questions on Eccentricity FAQs on Eccentricity What is Eccentricity? Eccentricity is the mathematical constant that is … Web4 apr. 2024 · The general equation of the hyperbola is: x 2 a 2 − y 2 b 2 = 1 Here, coordinates of foci are (±ae, 0). And eccentricity = e = 1 + b 2 a 2 Calculation: The equation 25x 2 - 4y 2 = 100 can be written as x 2 4 − y 2 25 = 1 This is the equation of a hyperbola. On comparing it with the general equation of hyperbola, we get ⇒ a 2 = 4 and b 2 = 25
Web20 feb. 2024 · Foci: A hyperbola has two foci whose coordinates are F(c, o), and F'(-c, 0). Center of a Hyperbola: The centre of a hyperbola is the midpoint of the line that joins the two foci. Major Axis: The length of the major axis of a hyperbola is 2a units.; Minor Axis: …
WebAbout Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How YouTube works Test new features Press Copyright Contact us Creators ... カッコいい おじさん 芸能人Web30 jan. 2024 · Equation of the hyperbola whose eccentricity is 5/4 focus (a,0) and directrix 4x-3y=a is 7y²+24xy-24ax-16ay+15a² = 0 Given, the eccentricity is 5/4 Focus is (a,0) Directrix is 4x - 3y - a = 0 So, the equation of the hyperbola would stand as: (x-a)² + (y … patooterWeb29 mrt. 2024 · The eccentricity is therefore 1 + ( 1 1) 2 = 2. More generally, for a hyperbola in standard position the slopes of the asymptotes are, as you’ve written, tan θ = ± b a. From this we have. e = 1 + b 2 a 2 = 1 + tan 2 θ = sec θ. The angle between the asymptotes is … pato ovalleWebIf the eccentricity of the standard hyperbola whose transverse axis is x− axis and passing through the point (4,6) is 2, then the equation of the tangent to the hyperbola at (4,6) is Q. The equation of the hyperbola whose foci are at (4,6), (4,−4) respectively and having … pa to orlando driveWebSet ep equal to the numerator in standard form to solve for x or y. Example 10.6.1: Identifying a Conic Given the Polar Form. For each of the following equations, identify the conic with focus at the origin, the directrix, and the eccentricity. r = 6 3 + 2sinθ. r = 12 4 … pato otorrinoWebFind the center, foci, vertices, co-vertices, major axis length, semi-major axis length, minor axis length, semi-minor axis length, area, circumference, latera recta, length of the latera recta (focal width), focal parameter, eccentricity, linear eccentricity (focal distance), … patoo thai ecclesall roadWebd) 4 x 2 - 5y 2 – x + 8y + 1 = 0. See Summaries on page 588. Eccentricity. A conic is the set of all points P(x, y)in a plane such that the ratio of the distance from P to a fixed point and the distance from P to a fixed line is constant. The constant ratio is called the … pato o\u0027ward super license points